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Whats (m4n2)1/2 square root of m2n2
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do you know this property \(\left(a^n\right)^{\frac{1}{m}}=a^{\frac{n}{m}}\)?
\[\sqrt{m^4n^2}=\left(m^4\right)^\frac{1}{2}\left(n^2\right)^\frac{1}{2}=~?\]
yeah I done that that's going to equal m2 n1... so do you times the m2 times m2 and n1 then times the n2?
\[m2 n1*m2n1\]
correct...
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thanks sooooo much!
np... :)
what about \[(8x3z9)2/3\]?
almost the same rule, we just multiply the exponents... \[(a^m)^n=a^{m\times n}\]
\[(8x^3z^9)^{\frac{2}{3}}=(8)^{\frac{2}{3}}(x^3)^{\frac{2}{3}}(z^9)^{\frac{2}{3}}=~?\]
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