Question

How do I find the integral of (1-2x^2)^3(x) dx

Answer 1

if it is
\[ \int (1-2x^2)^3 x \ dx \]

let \[ u = (1-2x^2) \\ du = -4x\ dx\]
and
\[ x\ dx= -\frac{1}{4} du \]
replace \( (1-2x^2) \) with \( u \)
replace \(x\ dx \) with \(-\frac{1}{4} du \)

Answer 2

Thankyou(: