Question

If A + B = 90°, sin A = p/q, cos B = r/s, the correct relation between p, q, r, s will be

Answer 1

same compendendo and dividendo rule ahh

Answer 2

sin^2+cos^2=1

Answer 3

is it given that ABC is a triangle or something ?

Answer 4

nope:)i was blindly saying

Answer 5

A + B = 90
A = 90 - B
sin(A) = sin(90-B)
= cosB

Answer 6

sinA = cosB

so simply equate :

p/q = r/s