Question

If x varies inversely as y and directly as t, and x = 12 when t = 10 and y = 25, find y when x is 6 and t = 3.

Answer 1

\[x=k\frac{ t }{ y }\]
\[12=k \frac{ 10 }{ 25 }\]
k=30
\[6=30(\frac{ 3 }{y })\]
\[6=\frac{ 90 }{y }\]
\[y=\frac{ 90 }{6 }\]
simplify to get y

hope you understand my steps