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OpenStudy (anonymous):
[Medal and Fan! please help] Solve by factoring. x^3+4x^2-x≥4
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OpenStudy (anonymous):
\[ x^3+4x^2-x≥4\] right ?
OpenStudy (anonymous):
it is tricky because it says "by factoring" but you have to subtract \(4\) and make it \(\geq 0\) before you start
OpenStudy (anonymous):
\[x^3+4x^2-x≥4\\ x^3+4x^2-x-4\geq 0\\ (x-1) (x+1) (x+4)\geq0\]
OpenStudy (anonymous):
then it should be easy
OpenStudy (anonymous):
wow ty! i got it
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