Question

[Medal and Fan! please help] Solve by factoring. x^3+4x^2-x≥4

Answer 1

\[ x^3+4x^2-x≥4\] right ?

Answer 2

it is tricky because it says "by factoring" but you have to subtract \(4\) and make it \(\geq 0\) before you start

Answer 3

\[x^3+4x^2-x≥4\\
x^3+4x^2-x-4\geq 0\\
(x-1) (x+1) (x+4)\geq0\]

Answer 4

then it should be easy

Answer 5

wow ty! i got it