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what value of k solves the equation k^-5 = 1/32
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\[k^{-5}=\frac{1}{k^5}=\frac{1}{32}\] which tells you \[k^5=32\]
thank you
What value of m solves the equation 2^m = 1/8
1/32^-(1/5) Or in other words to -5 root of 1/32 Alternatively the 5 root of 32 in other words 32^(1/5)
x^m = y Log base x of y = m
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the answer is 2. i just took the test, trust me.
Thank you @amberosales!
Lol no prob @jabez177
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