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a ball is thrown vertically upward from the ground. it's distance from the ground in t seconds is s= 16t^2+122t. after how many seconds will the ball be 160 feet from the group
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s is the distance from the ground that the ball is. They tell you that the ball is 160 feet from the ground and they want you to find the time that it is 160 feet from the ground. So you fill s in with 160 and solve for the time, t. Do you know how to do that?
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