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A car decelerates from a speed of 45 m/s to rest in 68 meters. What is the magnitude of its acceleration to one decimal place?
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Here, u=45m/s v=0 s=68m Plug in these values in the 3rd equation [\(v^2=u^2+2as\)] and solve it for a
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Working on it. :)
a = -14.9
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:O
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Surprised I got it, lol.
lol !
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