Solve the equation 2cosx-secx =1 on the interval [0,2pi).
The only four choices they give me to pick as an answer are A. 0, 2pi/3 B. 0, pi/6, 5pi/6 C. 0, 2pi/3, 4pi/9 and D. 0, pi/2, 3pi/2

Question

Solve the equation 2cosx-secx =1 on the interval [0,2pi). 
The only four choices they give me to pick as an answer are A.  0, 2pi/3  B. 0,  pi/6, 5pi/6  C. 0, 2pi/3, 4pi/9  and D. 0, pi/2, 3pi/2

amistre64 · Answer

write it all in terms of cos, and it should simplify to a quadratic

anonymous · Answer

what do you mea all in terms of cos

amistre64 · Answer

you have a cos function, and a sec function .... sec can be written in terms of cos

anonymous · Answer

how exactly would i write that

amistre64 · Answer

that is one of the basic trig properties that you should have in your material.  and that you should commit to memory.  sec = 1/cos

amistre64 · Answer

the rest is algebra

anonymous · Answer

thanks!