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Can some one please explain to me how to do trigonometric integrations like the integral of (4 cos(x)/(1+sin(x))?
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Let \(u = 1+\sin x\) \(du = \cos x \, dx \) :)
\[\large \int\frac{4\cos x}{\sin x}\, dx \] If \(u = 1 + sin x\) \(du = \cos x \, dx\) \[ \large \int\frac{4}{u}\, du\] and recall that: \[\int \frac{1}{x}\, dx=\ln|x|+C \]
thank you i think i understand it now (:
:)
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