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Completely factor the following. please help!!! 8x^3-27y^6
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\[8x ^{3}-27y^{6}\]
This looks like a difference of two cubes to me. Do you know the formula for that factorisation method?
I'll give you a starting point. \[a ^{3} - b ^{3} = (a-b)(a^2 + ab + b^2)\]
ohh ok ill try
what do i do with \[y^3\] left over?
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