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Help! Pre-Cal What are the zeros in f(x)=x^5+x^3-6x?
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what do we get when we factor a GCF?
Isn't the GCF 1?
i was going for x
f(x) = x(x^4 + x^2 -6) so we know x=0 makes this equal to 0 now to work the hidden quadratic, let a = x^2 such that a^2 + a - 6 = 0
So x(x^4+x^2-6)?
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yep
Oh ok I got it now, thank you!
youre welcome, good luck :)
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