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Given the function \[f (x) =\log_{4}(x + 8), \] find the value of \[f^{-1} (2)\]
\[\log_4(x+8)=2\] sovle for \(x\) in two steps
\(\Large \log_ab=c \implies b=a^c \)
write in equivalent exponential form as \[4^2=x+8\] and solve for \(x\) (now in one step)
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x = 8
thats correct :)
oh and thats your \(f^{-1}(2) \\ = 8\)
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