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Points: (-4,2) and (8,7) The slope is 5/12 Using slope intercept form y=5/12x + b what's b or is the equation just y=5/12x+b
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\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ -4}}\quad ,&{\color{blue}{ 2}})\quad &({\color{red}{ 8}}\quad ,&{\color{blue}{ 7}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\to {\color{green}{ \cfrac{5}{12}}} \\ \quad \\ y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form}\)
once you solve for "y", you'd see what "b" is
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