Question

e^xx^2+4xe^x=0

Answer 1

\[e^x \left( x^2+4x \right)=0\]
\[e^x \neq0~for~any~finite~real~value.\]
\[hence~x^2+4x=0,x \left( x+4 \right)=0\]
either x=0
or x=-4