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Algebra
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17. Given a slope of 13 and a y-intercept of -5, write the equation of the line in slope-intercept form. A. y = 13 - 5x B. y = 13x - 5 C. y = 13x + 5
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that means x=0 y=mx+c \[m=\frac{ \Delta y }{ \Delta x }\] \[13=\frac{ y--5 }{x-0 }\] cross multiply \[13(x)=y+5\] arrange it accordingly \[y=13x-5\]
:( @Mokeira good job
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