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Trigonometry 14 Online
OpenStudy (anonymous):

how do i solve cos2x-cosx=0 where the interval is 0 (less than or equal to) x (less than or equal to) 2 pi

OpenStudy (fibonaccichick666):

can you change the cos2x into something different?

OpenStudy (sanjanap):

x= pi/2

OpenStudy (anonymous):

@fibonaccichick66 i dont think so

OpenStudy (anonymous):

and @SanjanaP how did you get that

OpenStudy (fibonaccichick666):

Have you learned double angle identities?

OpenStudy (fibonaccichick666):

if not, I recommend looking that up to begin

OpenStudy (anonymous):

i have the formulas for double angle identities yes

OpenStudy (fibonaccichick666):

that is how you get rid of the 2x to begin

OpenStudy (anonymous):

have u learned the double angle formulas, cause thats how we can start

OpenStudy (fibonaccichick666):

so please, re-write the eq, using it

OpenStudy (anonymous):

im not sure how to apply the formulas to this problem. if you dont mind, can you explain it?

OpenStudy (fibonaccichick666):

well, what does cos2x=? by definition

OpenStudy (anonymous):

2sinxcosx

OpenStudy (fibonaccichick666):

for cosine?

OpenStudy (fibonaccichick666):

better check this http://www.purplemath.com/modules/idents.htm

OpenStudy (anonymous):

check that website out it has a lot of amazing features

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