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How many tangents are possible from the origin on the curve y=(x+1)^3 . Also find the equation of these tangents . HELP !
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this a calculus course?
Yes , its a question from application of derivatives.
a point on the curve looks like \((x, (x+1)^3)\) and the origin is \((0,0)\) the slope of the line between \((0,0)\) and \((x,(x+1)^3)\) is \(\frac{(x+1)^3}{x}\)
the slope of the line tangent to the graph will be \(3(x+1)^2\)
that being the derivative they have to be the same, set \[3(x+1)^2=\frac{(x+1)^3}{x}\] and solve for \(x\)
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Thanks a ton :)
yw, hope it is clear more or less
Yep , my answer matches :)
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