The distance for Jay to travel to Winsconsin is 720 miles. Due to weather and traffic, it took him 3 hours longer to return home at an average speed that was 20% slower that the average speed on the way up. What was the average speed on the trip there and the average speed on the way back?

Trip:RT Trip Back:(.8R)(T+3) Therefore RT=(.8R)(T+3)
Solve for R or T Then subsitute in the formula 720=RT

Question

The distance for Jay to travel to Winsconsin is 720 miles. Due to weather and traffic, it took him 3 hours longer to return home at an average speed that was 20% slower that the average speed on the way up. What was the average speed on the trip there and the average speed on the way back?

Trip:RT Trip Back:(.8R)(T+3) Therefore RT=(.8R)(T+3)
Solve for R or T Then subsitute in the formula 720=RT

cwrw238 · Answer

yes  thats the correct way to do this

cwrw238 · Answer

RT = 0.8RT + 2.4R
0.2RT = 2.4R
T = 2.4R / 0.2R  = 12

now  replace T  in the formula RT = 720 by 12  to get the Value of R

cwrw238 · Answer

R is the average speed on the way to Wisconsin and 0.8R speed on way back.