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Input the equation of the given line in standard form. The line through (1, -4) and parallel to 2x +3y = 4.
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1st find out the slope of the given line.
Write the equation 2x + 3y = 4 in the form : y = mx + c and u'll get m.
I tkink that line of equation have form 2x +3y = K If point (1, -4) lies on 2x +3y = K, K = 2*1+3*(-4) = 2-12=-10 So answer is: 2x +3y = -10 Explanation: normal vector of first line is (2,3) and paralel line have same normal vector;)
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