Question

you toss 4 coins in the air at the same time what is the probability of each of the classes occurring

4 heads
3heads: 1 tail
2heads: 2 tails
1head: 3 tails
4tails

Answer 1

even if though there are multiple combinations for the i figured the 4 heads and the 4 tails had a 1/16 chance of happening but i screwed up somewhere with the middle three because my over all chance of occurring comes out to 1.5. sorry i should have explained better earlier.

3heads: 1 tail
2heads: 2 tails
1head: 3 tails

Answer 2

1 3 6 3 1 = 14 total ways
and
4 heads = 1/14
4 tails = 1/14
3 heads 1 tail = 3/14
3 tails 1 head = 3/14
2 heads 2 tails = 6/14

Answer 3

ok thanks that explains where i messed up

Answer 4

there is a mistake
1 4 6 4 1 = 16 total ways
and
4 heads = 1/16
4 tails = 1/16
3 heads 1 tail = 4/16
3 tails 1 head = 4/16
2 heads 2 tails = 6/16

Answer 5

there is anotehr way

Answer 6

- - - -
4 spots
you will fill up with heads and tails which more than 1/2 success rate
so (1/2)^2 how every a different number of combinations that result in same outcome

for 3 heads 1 tail it is 4 choose 1
for 2 heads 2 tails it is 4Choose
for 4 heads, and 4 tilts its 4choose 0

Answer 7

soo
1/16*4choose0 = prob of 4 heads or 4 tails

Answer 8

1/16*4choose1 = prob of (3,1)
1/6 * 4C2 = prob of (2,2)

Answer 9

Awesome bro

Answer 10

@dan815