Question

Please help its my last assignment and I'm desperate
A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, ft, in feet, at different times t in seconds:
f(t)=-16t^2+34t+80

The average rate of change of f(t) from t=5 seconds to t=7 seconds is _____ feet per second.

Answer 1

\(\huge A(x)=\frac{f(x)-f(a)}{x-a}\)
A being the name of the average rate of change function

Answer 2

So whats the answer?

Answer 3

Plug in and find out what f(7) and f(5) are

Answer 4

how

Answer 5

f(t) = \(\large -16t^2+34t+80\)
f(7) = \(\large -16(7^2)+34(7)+80\)

Answer 6

so confused I'm sorry

Answer 7

I'll write it out

Answer 8

if we wanted the average rate of change from t=3 to t = 5
we would use the following: \(\huge A(x)=\frac{f(5)-f(3)}{5-3}\)

now what is f(5)? f(5) = \(\large -16(5^2)+34(5)+80)\)

Answer 9

i only have a min to submit :(

Answer 10

I'm not going to give you the answer :(

Answer 11

k thanks anyways

Answer 12

שלום

Answer 13

;~; שלום http://puu.sh/b9csX/2e982ab6ad.png

Answer 14

-582?

Answer 15

−16(7^2)+34(7)+80
-16*49=-784+238+80=-466

just plug it into a calculator... f(7) = -466

Answer 16

i did thats what i got

Answer 17

I have no idea what you're even doing right now.

find f(7) and f(5)