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Simplify the expression, and rationalize the denominator when appropriate.
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\[\sqrt{3x/2y ^{3}}\]
\[\sqrt[3]2x ^{4}y{^{4}}/9x\]
Oh and the second one, there all under the square root sign except for the exponent on the outside. Can you help @Cosmichaotic please, i don't understand these 2
Ok so with the first one, let's rewrite it like this so it may make more sense visually. \[\sqrt{3x}/\sqrt{2y ^{3}}\]
Or.|dw:1409101786359:dw|
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