How to make the parabola y= ax^2 + bx + c pass through (3, 13) and be tangent to the line 8x - y = 15 at (2, 1)?

Question

phi · Answer

Find the slope of the line 8x - y = 15.  call it m

find the derivative of the f(x)= parabola.  call it   f '(x)
set f '(2) = m

use the info  (3,13) is on the parabola to set up this equation
13= 9a +3b + c

also (2,1) is on the parabola, so you also have
1 = 4a +b + c

3 equations, and 3 unknowns can be solved

anonymous · Answer

Correct answer @phi , Keep it up. -Tim http://www.acadsoc.com

radar · Answer

@aoadal23 Let me know what you got for answer as I have worked it (I think lol)