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Physics 12 Online
OpenStudy (anonymous):

A proton travels at a speed of 2.0..*.10Ò meters/second. Its velocity is at right angles with a magnetic field of strength 5.5..*.10ȳ tesla. What is the magnitude of the magnetic force on the proton? A. 1.0x10^-15 newtons B. 1.8x10^-15 newtons C. 2.1x10^-16 newtons D. 5.5x10^-16 newtons

OpenStudy (schrodingers_cat):

\[F = qv \times B\]

OpenStudy (schrodingers_cat):

Since the velocity and magnetic field are perpendicular it simplifies to \[F = qvBsin(90) = qvB\]

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