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F(x)=3x+1 and f-1=x-1/3, then f(2)=
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f(2)=3*2+1=6+1=7
@keepsecure93
Ok what happen to the negative.
arcf=2-1/3=1/3
f^-1=arcf
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Ok
So in this one. F(x)=3x+1and f-x-1/3, then f-1(7). F(7)=3*7+1=21+1=22 is that right.
Evaluate 3[5+3[10+4*8]]
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