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A(n)=12+(n-1)(3)
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its a general term for an arithmetic series it can be simplified to A(n) = 3n + 9
the question is find the first fourth and tenth term of the arithmeticsequence described by the given rule
well substitute n = 1 for 1st n = 4 for 4th n = 10 for 10th
A IS 12,21,39 B is 3,24, 27 c is 12,24,22 d 0,9,27
well just do the substitution A(1) = 12 + (1 -1)*3 A(4) = 12 + (4 -1)*3 A(10) = 12 + (10 - 1)*3
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