Question

dr miller starts with 3.4 gallons of chlorine in his pool. each day he adds .25 gallons of chlorine and 15% evaporates. how much chlorine will be in his pool at the end of the sixth day

Answer 1

k, so first: set up the equation

Answer 2

what???

Answer 3

Start amount = 3.4 gal
add .25 gal daily
15 % of the total evaporates daily, lets assume after the .25 is added, so
multiply by 0.85 daily (0.85 + 0.15 = 1.0, so this will subtract the 15% )

Answer 4

so ur equation = (3.4 + 0.25 ) x 0.85 ... per day, the answer equals the start amount for the next day, (ie replaces the 3.4)...

Answer 5

\(\large x = (((((((3.4 + 0.25) \times 0.85) +0.25) \times 0.85) +0.25) \times 0.85) +0.25) \times 0.85) +0.25) \times 0.85) +0.25)\)

Answer 6

i got day 6 as 2.87698 gal, hbu?