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solve the following quadratic equation: 9x^2 - 49 = 0
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9x^2 - 49 = 0 (3x)^2 - 7^2 = 0 (use a^2-b^2) (3x-7)(3x+7) x=+_ 7/3
why is it 7/3?
(3x-7)(3x+7)=0 either (3x-7) =0 or (3x+7)=0
okay thank you :)
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