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Physics
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Chap 3 8)
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@aaronq
\(T_1\) is due to both objects under the force of gravity and \(T_2\) is only due to the 2 kg box.
Hw do I form the equation for T1
\(\sum F_y=T-F_g=0\)
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then use the mass of the boxes and the rope (if not massless) in \(F_g\)
40-T=4a T-20=2a Solve simutaneously
mg-T=ma T-mg=ma
why
|dw:1409246548770:dw|
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