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simplify: [(13x-4)/(6x^2-11x-10)] + [(3)/(5-2x)]
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This is what I have so far... 13x-4 3 ------ + ------- (3x+2)(2x-5) (-2x+5) 13x-4 -3(3x+2) ----- + ---------- (3x+2)(2x-5) (3x+2)(2x-5)
yeah, i know the answer. but i wanted to know how to get to it
\[\frac{ (13x+4)+3*-1*(3x+2) }{(3x+2)(2x-5)} = \frac{ 10x+5 }{ (3x+2)(2x-5) } \] okay so that's what i have. how do i get from here to 2/3x+2
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