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Please help me! I have no idea how to evem start it off. Question is let f(x)=-52x(x+3)^6(x-2)^3 a) determine the degree of f. B) identify all zero.
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well the equation has 3 zeros... x = 0, multiplicity 1 x = -2 multiplicity 6 its even so touches at x = -2 x = 3 multiplicity 3 the degree is the sum of the multiplicities.... so 10
hey campbell ty for your help i was wondering wouldnt the zeros be at x=2 and x=-3?
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