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how do i factor y(y^12-1) any further I asked something previously and have no clue how to go from here
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ur all set.that's ur answer
try a difference of squares
which in turn will prolly produce another difference of squares
the original question is y^13-y.... and brought it down to y(y^12-1) assuming that is correct
oh yea subtract 1 from12
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either the site is slow, or my internet connection is slow ...
y(y^6+1)(y^6-1) =>y(y^6+1)(y^3+1)(y^3-1) =>y(y^2+1)(y^4 - 3y^2+1)(y+1)(y^2-y+1)(y-1)(y^2+y+1)
@amistre64 its the site i couldn't load the site until just now
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