Question

Check this please

Answer 1

\[y^6+7y^3-8\]

Answer 2

\[(y^3-1)(y^3+8)\]

Answer 3

okay you can rewrite as difference or sum of cubes now

Answer 4

(y^3-1^3)(y^3+2^3)

Answer 5

if you remember we did example already on how to factor that, take a look at that again.

Answer 6

yes wait

Answer 7

\[(y^3-1) (y^6-y^3+1)\]

Answer 8

(y+2)^3

Answer 9

\[Y^2+2y-4\]

Answer 10

\[(y+2) (y^6-y^3+1)\]

Answer 11

wait no the finale answer is (y+2) (y^2+2y-4)

Answer 12

@dan815 finish helping x.x