Find the probability of randomly drawing the given marbles from a bag of 4 red,
6 green, and 2 blue marbles (a) with replacement and (b) without replacement.

26. a red, then a green

Question

Find the probability of randomly drawing the given marbles from a bag of 4 red,
6 green, and 2 blue marbles (a) with replacement and (b) without replacement.

26.  a red, then a green

across · Answer

There is a total of $12$ marbles in the bag. The probabilities without replacement are as follows:$$P(\text{red})=1/3,\P(\text{green})=1/2,\P(\text{blue})=1/6.$$Therefore, $P(\text{red and green})=1/6$. Can you do the one without replacement?

anonymous · Answer

thanks :)

anonymous · Answer

ok yeah dont know how to do the second part