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Factor: (8a^3b^3)-(27c^6d^6)
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\[8a ^{3}b ^{3}-27c ^{6}d ^{6}\]
Use the identity: \(\large x^3 - y^3 = (x-y)(x^2 + xy + y^2)\) \(\large (8a^3b^3)-(27c^6d^6) = (2ab)^3 - (3c^2d^2)^3 = ?\)
yep, follow @aum 's way
Put \(\large x = 2ab\) and \(\large y = 3c^2d^2\) on the right hand side of the identity mentioned in my previous reply.
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