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does anyone know how to solve this: 3^x+3=1/9 step by step and not just the answer
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\[\large 3^{(x+3)}=\frac{1}{9}\] Please confirm that this is the question.
yes, that is the question : )
\[\large3^{-1}=\frac{1}{3}\] \[\large3^{-2}=\frac{1}{3}\times\frac{1}{3}=\frac{1}{9}\] Can you see that: x + 3 = -2 ............(1) Now can you find the value of x by solving equation (1)?
okay, I got it thanks : ))
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