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n/3-8=-2
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\[\frac{ n }{ 3 }-8=-2\] \[\frac{ n }{ 3 }-8+8=-2+8\] \[\frac{ n }{ 3 }=6\] \[\frac{ n }{ 3 }*3=6*3\] \[n=18\]
If you meant this: \[\frac{ n }{ 3 - 8 } = 2\] then \[n = 2(3- 8) = 6 - 16 = -10\] otherwise @apple_pi is right
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