Question

I have 2 problems

Answer 1

first one is :
tgx+2ctgx-3=0
and the 2nd one is:
sinx-cosx=1/sqrt2

Answer 2

what are the directions?

Answer 3

i need to find all of the solutions

Answer 4

Ok...let me think....

Answer 5

sure

Answer 6

sin(x) + cos(x) = √2

Square both sides

sin²(x) + 2sin(x)cos(x) + cos²(x) = 2
1 + sin(2x) = 2 ------------ sin²(x) + cos²(x) = 1
sin(2x) = 1
2x = (4n+1)π/2
x = (4n+1)π/4

We have squared both sides so we need to check the answer

Odd values of n give us sin(x) + cos(x) = -√2
Even values of n give us sin(x) + cos(x) = √2

x = (8n+1)π/4

Answer 7

it's sinx-cosx=1/sqrt2

Answer 8

not +

Answer 9

Sorry, I found this on the web...I didn't solve it XD

Answer 10

Let me research more

Answer 11

okay :D

Answer 12

use the complementary angle method Rsinxcosa - Rcosxsina = Rsin(x-a) compare this with sinx - cos x = sqrt2 R cosa = 1 R sina = 1 so Rsina / Rcosa = tan a = 1 a = 45 degrees now you can find value of R and using Rsin(x - 45) = sqrt2 find x


I found this on this website XD

Answer 13

what is R??

Answer 14

could you write it as an equation?

Answer 15

sinx - cosx =sqrt(2) sin^2(x) -2cos(x)sin(x) + cos^2(x) = 2 sin^2(x)+cos^2(x) -2cos(x)sin(x)=2 1-2sinxcosx=2 -2sinxcosx=1 -2(0.5(sin(x+x)+sin(x-x))=1 using identities -sin2x+sin0=1 sin2x=-1 2x=-90 degrees + k360 x=-45 degrees + k180 or 2x=270 degrees +k360 x= 135 degrees + k180 where k is integer



Okay now I'm getting confused :/ Maybe I'll ask some person who knows math better then I know.

Answer 16

BRB

Answer 17

@ganeshie8, we need some math help....please?

Answer 18

we sure do xD

Answer 19

Lol....

Answer 20

Interesting how I'm so terrible in math and now I can't even find some silly equations....XD

Answer 21

the problem is that everyone is different if it was =1 it's different if it was sqrt2 it's not the same as 1/sqrt2
i tried to find it somewhere but i failed i even checked all of my books that's why i posted it here

Answer 22

there are similar ones but they only confuse you more XD

Answer 23

Yes, I'm already muddled up XD Hmmm...gotta go mention more people

Answer 24

@Abhisar be nice and and please help us out, we are mixed up XD

Answer 25

can we get some help ? ://
@ParthKohli @mathstudent55 @aaronq

Answer 26

well bummer :D

Answer 27

@uri

Answer 28

@undeadknight26 @nincompoop @iceicebaby

Answer 29

I have not learned this yet sorry ;-;

Answer 30

can you tell me who has?
i really need help with this i'll have a test in couple of days :O

Answer 31

I don't think I learned this either because this is way too tough. Man, what grade are you in buddy?

Answer 32

finished highschool

Answer 33

Lol.....I'm still in high school.....

Thanks for the medal, I don't think I helped though XD

Answer 34

oh i think Abhisar gave you the medal :D

Answer 35

Lol...

Answer 36

can you help me with these?
@Mason_Jones573

Answer 37

Alright, what do you need help with?

Answer 38

the first two

Answer 39

tgx+2ctgx-3=0
and the 2nd one is:
sinx-cosx=1/sqrt2

Answer 40

i need to find all of the solutions