Question

4(x-2)/x-3+3/x=-3/x(x-3)

Answer 1

isn't that you question

Answer 2

idistribute x-2 by 4 frst of all

Answer 3

multiply every term by x(x -3) and cancelling common factors you get

\[4(x -2)\times x + 3(x -2) = -3\]

now distribute and collect like terms

\[4x^2 - 5x - 3 = 0\]

now solve

Answer 4

oops slight error

\[4x(x - 2) + 3(x -3) = -3\]

so its

\[4x^2 - 5x -6 = 0\]

now solve

Answer 5

the quadratic factors... so you can find the solutions by factoring... or using the general quadratic formula...