Question

suppose z varies directly with x and interversley with y when x=6 and y=2 and z=15 find z when x=4 and y=p????

Answer 1

\(\large z = k * \Large \frac xy\)
Substitute x = 6, y = 2, z = 15 and find the constant of proportionality k.
\(\large 15 = k * \Large \frac 62 = 3k\)
\(k = 5 \)
\(\large z = 5 * \Large \frac xy\)
Substitute x=4 and y=p
\(\large z = 5 * \Large \frac 4p = \frac{20}{p}\)

Answer 2

thank you so much!

Answer 3

you are welcome.