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OpenStudy (anonymous):
prove cosA x cos2A x cos4A x cos8A = sin16A/16sinA
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OpenStudy (dawnr):
i think you can google this
OpenStudy (jmark):
Given cosA x cos2A x cos4A x cos8A = sin16A/16sinA RHS sin16A/16sinA [2sin8A cos 8A]/16sinA [cos8A(2sin4A cos4A)]/8sinA [cos8A cos 4A(2 sin 2A cos 2A)]/4sinA [cos 8A cos 4A cos 2A(sin2A)]/2 sinA [cos8A cos 4A cos 2A(2sinA cos A)]/2 sin A cos A cos 2A cos 4A cos 8A Hence RHS=LHS ICSE Question Papers Class 9 - http://education-help-online.blogspot.in/2014/09/icse-question-papers-class-9.html
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