Question

Find the product (2x-1)(x-1)

Answer 1

yolo solo the hobo

Answer 2

FOIL!

Answer 3

Do you know how to distribute

Answer 4

no she dont

Answer 5

\((a+b)(c+d)=ac+ad+bc+bd\)

Answer 6

yea

Answer 7

surely you have seen this many times?

Answer 8

yes! i just don't know which variable each is

Answer 9

what is \(a*a=?\)

Answer 10

2a

Answer 11

1a

Answer 12

incorrect?

Answer 13

that is \(a+a=2a\)

Answer 14

oh okay??

Answer 15

\(a*a=a^2\) right?

Answer 16

yes! thats what i meant to put! i forgot how to do the ^

Answer 17

well addition is different than multiplication xD

Answer 18

lol I know

Answer 19

okay!
so what is \(2x*x=?\)

Answer 20

2^2

Answer 21

first let's apply what we have written above okay
\((2x-1)(x-1)=2x*x+2x*(-1)+-(1)*x+(-1)*(-1)\)

Answer 22

I used distributive property that i wrote above with a,b,c,d
same thing with our case!

Answer 23

No wrong \(2x*x=2*(x*x)=2x^2\)

Answer 24

remember i wrote \(a*a=a^2\)
same with \(x\)

Answer 25

yolo

Answer 26

lol I am so confused

Answer 27

its causee your a blonde

Answer 28

okkkk

Answer 29

hehe!
this is all just like playing a game
they give us a definition and property, and we now have something to play with haha
the game is \((a+b)(c+d)=ac+ad+bc+bd\) that's rule #1
rule #2 \(a*a=a^2\) multiplying a number by it self
rule #3 \((-)*(+)=(-)\\ (+)*(+)=(+)\\ (-)*(-)=(+)\)
this * i meant multiplication okay

Answer 30

Now they one us to play this game knowing this facts!

Answer 31

if i tell about a card game rules you would understand the rules first
then play the the card game^_^
if i didn't give any rule you will not be able to play it right?

Answer 32

seems my effort and energy was wasted! but anyway... good luck