Question

Help evaluating

Answer 1

whatever \[\large \frac{2}{\left(\frac{1}{3}\right)^2+4}\] is

Answer 2

as satellite73 pointed out \(\bf g(x)=\cfrac{2}{x^2+4}\qquad x={\color{brown}{ \frac{1}{3}}}\implies g\left({\color{brown}{ \frac{1}{3}}}\right)=\cfrac{2}{\left({\color{brown}{ \frac{1}{3}}}\right)^2+4}\)

Answer 3

sorry back

Answer 4

i got .49

Answer 5

or 18/37