Question

(sin^2x -4sinx+4 )/sinx-2

Answer 1

Simplify

Answer 2

\[
\frac{\sin^2(x) - 4\sin(x) + 4}{\sin(x) - 2}
\]Let a = sin(x)
\[
\frac{\sin^2(x) - 4\sin(x) + 4}{\sin(x) - 2} = \frac{a^2 - 4a + 4}{a-2} =
\frac{(a-2)^2}{a-2} = a-2 = \sin(x) - 2
\]

Answer 3

Thank you so much.

Answer 4

You are welcome.

Answer 5

Can I interpret others problems like this as well. By replacing with a variable