Question

\[(a^2 - b^2) \sin\theta + 2ab\cos \theta = a^2 + b^2\]\[\tan \theta = ?\]

Answer 1

All the terms looks funny to me. Just a hint would work.

Answer 2

well tan is sinx/cosx try to pull out sin and cos out of it and put it back in tan

Answer 3

how

Answer 4

tanθ-=a2-b2/2ab
I think that's right I just learned this stuff

Answer 5

how

Answer 6

Thanks for Googling it for me.

Answer 7

@Mashy

Answer 8

do you maybe know someone who can help me with trig?

Answer 9

I can help you, but I myself am stuck with it...

Answer 10

http://openstudy.com/updates/5404b92de4b0f2ed1e146373

Answer 11

http://openstudy.com/study#/updates/501a2110e4b02742c0b1a836

Answer 12

Thanks, gotcha!