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find the derivative of f(x) = |x|
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f(x) = x when x>0 -x when x<0 f'(x) = 1 when x>0 -1 when x<0 So f'(x) = sign(x)
but what's the derivative?
What I said above. Derivative of f(x) equals sign(x).
how would you show that using the f(x+h)-f(x)/h equation
Are you asked specifically to do it that way ?
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yea
Sorry couldn't get it with that method, but simply deriving f you get: f'(x) = 1 when x>0 -1 when x<0
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