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Mathematics 20 Online
OpenStudy (goldps):

rewrite expression without using absolute value: |(x-2)(x-3)| if 2

OpenStudy (anonymous):

if x is between 2 and 3, then \(x-2\) is positive, and \(x-3\) is negative, so the product is negative

OpenStudy (anonymous):

that makes \[|(x-2)(x-3)=-(x-2)(x-3)\]

OpenStudy (goldps):

ok ty.

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