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evaluate for x=3, y=2, and z=1 (yz)^2
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i think it is 4 not sure
its 4
but how do i get it
multiply 1 times 2 and square it and you get four so 2 times 1 is 2 square it its 4
(2*1)^2= 2^2= 2*2= 4
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ohhhh so i would do [(2)(1)]^2 then i would so [2]^2 then i would get 4
right or you could simply do it the way i did too! but ya! :)
thank you so much :)
your welcome
do you have anymore questions?
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not at this moment but thanks for your help :)
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