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how do you solve 6/b-1=9/7?
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answer is 42/16 which is equal to 21/8
\[\large \frac{6}{b-1}=\frac{9}{7}\iff 9(b-1)=6\times 7\]
pretty sure the above answer is wrong
i would think so
\[9b-9=42\\ 9b=51\\ b=\frac{51}{9}=\frac{17}{3}\]
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